有个细节，就是query的时候的顺序，不注意到直接T飞，分析知道如果它只在一边的话你直接一边

可以保证复杂度

#include<iostream>
#include<cstring>
#include<algorithm>


const int N = 2e5+10;
using namespace std;
using ll = long long;
int n;
int a[N],b[N];
int tr[2][N<<2];


inline void pushup(int op,int u){
	if(!op)tr[0][u] = max(tr[0][u<<1],tr[0][u<<1|1]);
	if(op)tr[1][u] = min(tr[1][u<<1],tr[1][u<<1|1]);
}


inline void build(int op,int u,int l,int r){
	
	if(l==r){
		if(!op)tr[op][u] = a[l];
		else tr[op][u] = b[l];
		return;
	}
	int mid = (l+r)>>1;
	build(op,u<<1,l,mid),build(op,u<<1|1,mid+1,r);
	pushup(op,u);
}

int hackt;
inline int query(int op,int u,int l,int r,int ql,int qr){
	
	
	if(ql<=l&&r<=qr)return tr[op][u];
	
	
	int mid = (l+r)>>1;
	
	if(qr<=mid)return query(op,u<<1,l,mid,ql,qr);
	else if(ql>mid)return query(op,u<<1|1,mid+1,r,ql,qr);
	else{
		if(!op)return max(query(op,u<<1,l,mid,ql,qr),query(op,u<<1|1,mid+1,r,ql,qr));
		else return min(query(op,u<<1,l,mid,ql,qr),query(op,u<<1|1,mid+1,r,ql,qr));
	}
	
	
}



int main()
{
	ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
	cin>>n;
	for(int i=1;i<=n;i++)cin>>a[i];
	for(int i=1;i<=n;i++)cin>>b[i];
	build(0,1,1,n);
	build(1,1,1,n);

	
	
	ll res = 0;
	for(int i=1;i<=n;i++){
		if(a[i]>b[i])continue;
		int l=i-1,r=n+1;
		while(l+1!=r){
			int mid = (l+r)>>1;
			int tem1 = query(0,1,1,n,i,mid);
			int tem2 = query(1,1,1,n,i,mid);
			if(tem1<tem2)l = mid;
			else r = mid;
		}
 		
		 int ans_l = l+1;
 		
		l = i-1,r = n+1;
		while(l+1!=r){
			int mid = (l+r)>>1;
			int tem1 = query(0,1,1,n,i,mid);
			int tem2 = query(1,1,1,n,i,mid);
			if(tem1<=tem2)l = mid;
			else r = mid;
		}
 		
		 int ans_r = l;
		
 		
		 if(ans_l>ans_r)continue;
		if(query(0,1,1,n,i,ans_l)!=query(1,1,1,n,i,ans_l))continue;
		res = res + ans_r-ans_l+1;
		
	 }
	
	cout<<res<<"\n";
	
	
	
}