因为：

    f=0b1001110
    # 十进制 int()
    a=0*2**0+1*2**1+1*2**2+1*2**3+0*2**4+0*2**5+1*2**6
    print(a)
    # 八进制 oct()
    print(78/8,78%8)
    # 110 001 001  8 116
    print(1*2**0+0*2**1+0*2**2,1*2**0+0*2**1+0*2**2,0*2**0+1*2**1+1*2**2)
    #十六进制 hex()
    #0 100 1110 16 4E
    print(sixteenFoo(0*2**0+0*2**1+1*2**2),sixteenFoo(0*2**0+1*2**1+1*2**2+1*2**3))

所以：

# encoding: utf-8
# 版权所有 2024 涂聚文有限公司
# 许可信息查看：
# 描述：
# Author    : geovindu,Geovin Du 涂聚文.
# IDE       : PyCharm 2023.1 python 3.11
# Datetime  : 2024/6/22 20:01
# User      : geovindu
# Product   : PyCharm
# Project   : pyBaiduAi
# File      : BinaryConvert.py
# explain   : 学习
import sys
import os
import io


class BinaryConvert(object):
    """
    进制转换
    """
    def __init__(self):
        """
        实例化
        """
        self.numstr=''

    @staticmethod
    def hexFoo(k: int) -> str:
        """
        整数十六進制
        :param k:
        :return:
        """
        # hexStr=['0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F']
        hexStr = '0123456789ABCDEF'
        return hexStr[k]
    @staticmethod
    def hexFoo2(k: int) -> str:
        """
        整数转十六進制
        :param k: 整数
        :return:
        """
        fstr = ''
        if k == 10:
            fstr = "A"
        elif k == 11:
            fstr = "B"
        elif k == 12:
            fstr = "C"
        elif k == 13:
            fstr = "D"
        elif k == 14:
            fstr = "E"
        elif k == 15:
            fstr = "F"
        else:
            fstr = str(k)
        return fstr

    @staticmethod
    def DecimalConvert(numstr) -> int:
        """
        二进制字符串转十进制 字符串未倒过来  Octal  Decimal Binary   hexadecimal; sexadecimal
        :param numstr: 二进制字符 倒过来计算。从0开始索引
        :return:整数
        """
        getstr = ""
        lenght = len(numstr)
        ssum=0
        if lenght>0:
            if BinaryConvert.isBinary(numstr):
                index=0
                for k in range(lenght-1,-1,-1 ):
                    if numstr[k] == '1':
                        ssum = ssum+1 * 2 ** index
                    if numstr[k] == '0':
                        ssum = ssum+ 0
                    index+=1
        return ssum

    @staticmethod
    def OctalConvert(numstr:str) -> str:
        """
         二进制字符串转八进制   字符串未倒过来
        :param numstr:二进制字符
        :return:
        """
        length=len(numstr)
        eight = ""
        if length>0:
            cc=0
            if BinaryConvert.isBinary(numstr):
                for k in range(length, -1, -3):
                    if k >= 3:
                        #print(k, DecimalCovert(numstr[k - 3:k]))
                        eight = eight + str(BinaryConvert.DecimalConvert(numstr[k - 3:k]))
                    if 0<k < 3:
                        #print(DecimalCovert(numstr[:k]))
                        eight = eight + str(BinaryConvert.DecimalConvert(numstr[:k]))
                    cc+=1

        return eight[::-1]

    @staticmethod
    def HexadecimalConvert(numstr:str) -> str:
        """
        二进制字符串转十六进制 字符串未倒过来
        :param numstr:进制字符串
        :return:
        """
        sixtee = ""
        length = len(numstr)
        cc = 0
        if length>0:
            if BinaryConvert.isBinary(numstr):
                for k in range(length, -1, -4):  # 1 次处理一位
                    # print(k, sixteenFoo(threeCovert(numstr[k - 4:k])))
                    if k >= 4:
                        sixtee = sixtee + BinaryConvert.hexFoo(BinaryConvert.DecimalConvert(numstr[k - 4:k]))
                    if 0<k < 4:
                        #print(hexFoo(DecimalConvert(numstr[:k])))
                        sixtee = sixtee + BinaryConvert.hexFoo(BinaryConvert.DecimalConvert(numstr[:k]))
                    cc += 1
        return sixtee[::-1]

    @staticmethod
    def ReversedConvert(numstr:str) -> int:
        """
        二进制字符串转十进制 字符串倒过来
        :param numstr:  二进制字符
        :return: 整数
        """
        lenght = len(numstr)
        ssum = 0
        if lenght > 0:
            if BinaryConvert.isBinary(numstr):
                for k in range(0,lenght):
                    if numstr[k]=='1':
                        ssum=ssum+1*2**k
                    if numstr[k]=='0':
                        ssum=ssum+0
        return ssum

    @staticmethod
    def isBinary(numstr: str) -> bool:
        """
        判断是否二进制字符串，必须包含为1或0
        :param numstr:二进制字符串
        :return: 是否为真
        """
        length = len(numstr)
        isok = False
        if length > 0:
            for k in range(0, len(numstr)):
                if numstr[k] == '0' or numstr[k] == '1':
                    isok = True
                else:
                    isok = False
                    break
        return isok

    @staticmethod
    def SixConvertTen(hexadecimalstr:str) -> int:
        """
        十六制转十进制
        :param hexadecimalstr: 十六进制字符串
        :return: 返回整数
        """
        table = {'0': 0, '1': 1, '2': 2, '3': 3,
                 '4': 4, '5': 5, '6': 6, '7': 7,
                 '8': 8, '9': 9, 'A': 10, 'B': 11,
                 'C': 12, 'D': 13, 'E': 14, 'F': 15}

        #hexadecimal = '3B'  # input("Enter Hexadecimal Number: ").strip().upper()
        reInt = 0
        # computing max power value
        size = len(hexadecimalstr) - 1
        if size>0:
            for num in hexadecimalstr:
                reInt = reInt + table[num] * 16 ** size
                size = size - 1
        print("十六进制转十进制", reInt)
        return reInt

    @staticmethod
    def hexadecimalConvertTen(hexadecimalstr: str) -> int:
        """
         十六制转十进制
        :param hexadecimalstr: 十六进制字符串
        :return:
        """
        #hex = '3B'  # input("Enter Hexadecimal Number: ")
        c = count = i = 0
        lenght = len(hexadecimalstr) - 1
        while lenght >= 0:
            if hexadecimalstr[lenght] >= '0' and hexadecimalstr[lenght] <= '9':
                rem = int(hexadecimalstr[lenght])
            elif hexadecimalstr[lenght] >= 'A' and hexadecimalstr[lenght] <= 'F':
                rem = ord(hexadecimalstr[lenght]) - 55
            elif hexadecimalstr[lenght] >= 'a' and hexadecimalstr[lenght] <= 'f':
                rem = ord(hexadecimalstr[lenght]) - 87
            else:
                c = 1
                break
            count = count + (rem * (16 ** i))
            lenght = lenght - 1
            i = i + 1

        return count


    @staticmethod
    def hexadecimalConvertBin(hexadecimalstr: str) -> str:
        """
        十六制转二进制
        :param hexadecimalstr:
        :return:
        """

        hexDict = {'0': '0000', '1': '0001', '2': '0010', '3': '0011', '4': '0100', '5': '0101', '6': '0110',
                    '7': '0111',
                    '8': '1000', '9': '1001', 'a': '1010', 'b': '1011', 'c': '1100', 'd': '1101', 'e': '1110',
                    'f': '1111'}
        binary = ''
        if len(hexadecimalstr)>0:
            hexadecimalstr = hexadecimalstr.lower()  # '3b'
            for digit in hexadecimalstr:
                binary += hexDict[digit]
        print(binary)
        return binary

    @staticmethod
    def DecimalConvertBin(numint:int) -> str:
        """
        十进制转二进制字符串
        :param numint:
        :return:
        """
        #numint = 59
        numstr = []
        binstring = ''
        while numint > 0:           
            renum  = numint % 2
            numstr.append(renum )
            numint = numint // 2
        while len(numstr) > 0:           
            binstring = binstring + str(numstr.pop())
        return binstring


    @staticmethod
    def DecimalConvertOct(numint: int) -> str:
        """
        十进制转八进制
        :param numint:
        :return:
        """
        #numint = 59
        numstr = []
        octtring = ''
        while numint > 0:           
            renum = numint % 8
            numstr.append(renum )
            numint = numint // 8
        while len(numstr) > 0:            
            octtring = octtring + str(numstr.pop())
        return octtring

    @staticmethod
    def DecimalConvertHex(numint: int) -> str:
        """
        十进制转十六进制
        :param numint:
        :return:
        """
        #numint = 59
        numstr = []
        hexstring = ''
        while numint > 0:           
            renum = numint % 16
            numstr.append(BinaryConvert.hexFoo(renum))
            numint = numint // 16
        while len(numstr) > 0:           
            hexstring = hexstring + str(numstr.pop())
        return hexstring