题目描述

给定一个字符串 s ，请你找出其中不含有重复字符的 最长子串 的长度。

示例 1:

输入: s = "abcabcbb"
输出: 3
解释: 因为无重复字符的最长子串是 "abc"，所以其长度为 3。

示例 2:

输入: s = "bbbbb"
输出: 1
解释: 因为无重复字符的最长子串是 "b"，所以其长度为 1。

示例 3:

输入: s = "pwwkew"
输出: 3
解释: 因为无重复字符的最长子串是 "wke"，所以其长度为 3。请注意，你的答案必须是 子串 的长度，“pwke” 是一个子序列，不是子串。

提示：

0 <= s.length <= 5 * 10^4
s 由英文字母、数字、符号和空格组成

题解

滑动窗口

代码

// Function to find the length of the longest substring without repeating characters
int lengthOfLongestSubstring(char *s)
{
    int left = 0; // Initialize the left pointer of the sliding window
    int right = 0; // Initialize the right pointer of the sliding window
    int max = 0; // Initialize the maximum length of the substring
    int i, j;
    int len = strlen(s); // Get the length of the input string
    int haveSameChar = 0; // Flag to indicate if there are repeating characters

    for (i = 0; i < len; i++)
    {
        if (left <= right)
        {
            haveSameChar = 0; // Reset the flag for repeating characters

            // Check for repeating characters within the current window [left, right]
            for (j = left; j < right; j++)
            {
                if (s[j] == s[right])
                {
                    haveSameChar = 1; // Set the flag if a repeating character is found
                    break;
                }
            }

            if (haveSameChar)
            {
                // Move the left pointer to the next position after the repeating character
                left = j + 1;
            }
        }

        // Update the maximum length of the non-repeating substring
        max = max < (right - left + 1) ? (right - left + 1) : max;

        right++; // Expand the window by moving the right pointer
    }

    return max; // Return the length of the longest substring without repeating characters
}

作者：我自横刀向天笑
链接：https://leetcode.cn/problems/longest-substring-without-repeating-characters/solutions/1192065/wu-zhong-fu-zi-fu-de-zui-chang-zi-chuan-u22kb/
来源：力扣（LeetCode）
著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。