需求：横向纵向都可以求和，剩余分数为100减去纵向之和 

var arr = [
  {
    id: '张丹',
    rowInfo: [
      { realScore: 12 },
      { realScore: 34 },
      { realScore: 0 },
      { realScore: 0 },
      { realScore: 0 },
    ],
  },
  {
    id: '丽丽',
    rowInfo: [
      { realScore: 0 },
      { realScore: 0 },
      { realScore: 0 },
      { realScore: 0 },
      { realScore: 12 },
    ],
  },
];

var columnSums = [];

// 遍历数组的每个索引位置
for (var i = 0; i < arr[0].rowInfo.length; i++) {
  var columnSum = 0;

  // 遍历数组的每个对象，获取相同索引位置的元素，并求和
  for (var j = 0; j < arr.length; j++) {
    columnSum += arr[j].rowInfo[i].realScore;
  }

  columnSums.push(columnSum);
}

console.log("纵向求和结果：" + columnSums); // 输出：纵向求和结果：[12, 34, 0, 0, 12]