题目
请你判断一个 9 x 9
的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。
- 数字
1-9
在每一行只能出现一次。 - 数字
1-9
在每一列只能出现一次。 - 数字
1-9
在每一个以粗实线分隔的3x3
宫内只能出现一次。(请参考示例图)
注意:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 空白格用
'.'
表示。
示例 1:
输入:board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:true
示例 2:
输入:board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:false 解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
提示:
board.length == 9
board[i].length == 9
board[i][j]
是一位数字(1-9
)或者'.'
代码
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
bool isValidSudoku(char **board, int boardSize, int *boardColSize);
int main()
{
char *board[] =
{"....5..1.",
".4.3.....",
".....3..1",
"8......2.",
"..2.7....",
".....2...",
".6....28.",
".2.9.....",
"..4......"};
int t, *te;
printf("%d", isValidSudoku(board, t, te));
return 0;
}
bool isValidSudoku(char **board, int boardSize, int *boardColSize)//后两个参数没有用
{
int rownums[10], colnums[10];
memset(rownums, 0, sizeof(rownums));
memset(colnums, 0, sizeof(colnums));
for (int i = 0; i < 9; i++)
{
for (int j = 0; j < 9; j++)
{
if (board[i][j] != '.')
{
int number = board[i][j] - '0';
if (rownums[number] == 0)
{
rownums[number] = 1;
}
else
return false;
}
if (board[j][i] != '.')
{
int number = board[j][i] - '0';
if (colnums[number] == 0)
{
colnums[number] = 1;
}
else
return false;
}
}
memset(rownums, 0, sizeof(rownums));
memset(colnums, 0, sizeof(colnums));
}
int i = 0, j = 0;
for (int p = 3; p <= 9; p = p + 3)
{
for (int q = 3; q <= 9; q = q + 3)
{
i=p-3;
for (; i < p; i++)
{
j=q-3;
for (; j < q; j++)
{
if (board[i][j] != '.')
{
int number = board[i][j] - '0';
if (rownums[number] == 0)
{
rownums[number] = 1;
}
else
return false;
}
}
}
memset(rownums, 0, sizeof(rownums));
}
}
return true;
}