蓝桥杯其他真题点这里👈

//偶数行需要反转，判断行数时,最后一个需要特判,可以用向上取整
//也可以把传入的值减一,下标从0开始
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main{
    static int w,m,n;
    static BufferedReader in = new BufferedReader(
            new InputStreamReader(System.in));
    public static void main(String[] args) throws IOException {
        String[] init = in.readLine().split(" ");
        w = Integer.parseInt(init[0]);
        m = Integer.parseInt(init[1]);
        n = Integer.parseInt(init[2]);
        m--;
        n--;
        
        int x1 = m / w; //这么写的话 0 ~ w - 1算一层,所以上面的m和n需要先 - 1
        int y1 = m % w; //先这么写,下标为0 ~ w - 1正序,通过x1判断是否需要反转
        int x2 = n / w;
        int y2 = n % w;
        
        if (x1 % 2 == 0) y1 = (w - 1) - y1; //此时反转,下标为0~w-1

        if (x2 % 2 == 0) y2 = (w - 1) - y2; //0转到 (w - 1) - 0  1 转到 (w - 1) - 1
                                            //比如0转到5,1转到4
        System.out.println(Math.abs(x1 - x2) + Math.abs(y1 - y2));
        in.close();
    }
}