目标：取json中所有的Name、Age字典

思路：递归处理字典中直接包含子字典的情况，

import json


def find_targ_dicts(data,key1,key2):
    result = {}
    if isinstance(data, dict):
        if key1 in data and key2 in data: # 第一层字典中包含key1和key2
            result[key1] = data[key1]
            result[key2] = data[key2]
            yield result
        for k, v in data.items():
            yield from find_targ_dicts(v, key1, key2) # 递归处理子字典
    elif isinstance(data, list):
        for item in data:
            yield from find_targ_dicts(item, key1, key2)


# 示例JSON数据
json_data = '''
{
    "name": "mkdm",
    "age": 30,
    "children": [
        {
            "name": "Ace",
            "age": 10
        },
        {
            "name": "Bob",
            "age": 8
        },
        {
            "tt":{"name": "coh",
            "age": 9}
        }
    ],
    "address": {
        "city": "shbj",
        "addr": "sccd"
    }
}
'''

# 将JSON字符串转换为Python对象
data = json.loads(json_data)

# 提取所有的字典
dicts = list(find_targ_dicts(data,'name','age'))
print(dicts)
# 打印所有的字典
for d in dicts:
    print(d)

结果截图：