大纲
- 题目
- 地址
- 内容
- 解题
- 代码地址
题目
地址
https://leetcode.com/problems/pascals-triangle/description/
内容
Given an integer numRows, return the first numRows of Pascal’s triangle.
In Pascal’s triangle, each number is the sum of the two numbers directly above it as shown:
Example 1:
Input: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
Example 2:
Input: numRows = 1
Output: [[1]]
Constraints:
- 1 <= numRows <= 30
解题
这题就是按照层数构造出一个帕斯卡三角。逻辑也很简单,就是两边都是1,中间元素都是由上一层元素两两相加而得。
#include <vector>
#include <numeric>
using namespace std;
class Solution {
public:
vector<vector<int>> generate(int numRows) {
vector<vector<int>> result;
result.push_back({1});
for (int i = 2; i <= numRows; i++) {
vector<int> row(i, 1);
adjacent_difference(result[i-2].begin(), result[i-2].end(), row.begin(), plus<int>());
result.push_back(row);
}
return result;
}
};
这儿我们使用到C++17引入的std::adjacent_difference。它可以使用自定义的运算符计算区间内(__first,__last)相邻的两个元素,然后将其结果保存在另外一个迭代器(__result)的下一个位置。
/**
* @brief Return differences between adjacent values.
*
* Computes the difference between adjacent values in the range
* [__first,__last) using the function object @p __binary_op and writes the
* result to @p __result.
*
* @param __first Start of input range.
* @param __last End of input range.
* @param __result Output sum.
* @param __binary_op Function object.
* @return Iterator pointing just beyond the values written to result.
*/
// _GLIBCXX_RESOLVE_LIB_DEFECTS
// DR 539. partial_sum and adjacent_difference should mention requirements
template<typename _InputIterator, typename _OutputIterator,
typename _BinaryOperation>
_GLIBCXX20_CONSTEXPR
_OutputIterator
adjacent_difference(_InputIterator __first, _InputIterator __last,
_OutputIterator __result, _BinaryOperation __binary_op)
{
typedef typename iterator_traits<_InputIterator>::value_type _ValueType;
// concept requirements
__glibcxx_function_requires(_InputIteratorConcept<_InputIterator>)
__glibcxx_function_requires(_OutputIteratorConcept<_OutputIterator,
_ValueType>)
__glibcxx_requires_valid_range(__first, __last);
if (__first == __last)
return __result;
_ValueType __value = *__first;
*__result = __value;
while (++__first != __last)
{
_ValueType __tmp = *__first;
*++__result = __binary_op(__tmp, _GLIBCXX_MOVE_IF_20(__value));
__value = _GLIBCXX_MOVE(__tmp);
}
return ++__result;
}
代码地址
https://github.com/f304646673/leetcode/tree/main/118-Pascal’s-Triangle