https://leetcode.cn/problems/trapping-rain-water/description/
class Solution {
public:
int trap(vector<int>& height) {
int n = height.size();
// 预处理数组
vector<int> lefts(n, 0);
vector<int> rights(n, 0);
// 预处理记录左侧最大值
lefts[0] = height[0];
for (int i = 1; i < n; ++i) {
lefts[i] = max(lefts[i-1], height[i]);
}
// 预处理记录右侧最大值
rights[n-1] = height[n-1];
for (int i = n - 2; i > 0; --i) {
rights[i] = max(rights[i+1], height[i]);
}
// 将每个柱子可以接到水的值进行累加
int ret = 0;
for (int i = 0; i < n; ++i)
{
if (min(lefts[i], rights[i]) - height[i] > 0)
ret += min(lefts[i], rights[i]) - height[i];
}
return ret;
}
};