Problem - D - Codeforces

大致题目意思：找#的圆心

#include<bits/stdc++.h>
typedef long long ll;

#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
const ll N=1e2+1;
char a[N][N];
using namespace std;

int main()
{
    IOS;
    int t;
    cin>>t;
    while(t--)
    {
        ll fsth=0,fstl=0;
        ll n,m;
        cin>>n>>m;
        for(ll i=1;i<=n;i++)
        {
            for(ll j=1;j<=m;j++)
            {
                cin>>a[i][j];
            }
        }

        for(ll i=1;i<=n;i++)
        {
            for(ll j=1;j<=m;j++)
            {
                if(a[i][j]=='#')
                {
                    fsth=i;
                    fstl=j;
                    break;
                }
            }
            if(fsth!=0) break;
        }
        //cout<<fsth<<"hang";
        ll x,y;
        for(ll i=fsth;i<=n;i++)
        {
            if(a[i][fstl]!='#')
            {
                x=i-1;
                break;
            }
            
            if(i==n) x=n;
        }
        //cout<<x<<"zheli";
        y=(x+fsth)/2;

        cout<<y<<" "<<fstl;
        cout<<endl;
    }
    return 0;
}

存在问题：数组开太大，2e5

ac代码

#include<bits/stdc++.h>
typedef long long ll;

#define IOS ios::sync_with_stdio(0),cin.tie(0),cout.tie(0)
const ll N=1e2+1;
using namespace std;

int main()
{
    IOS;
    int t;
    cin>>t;
    while(t--)
    {
        ll n,m;
        cin>>n>>m;
        ll mx[2]={1,1},mi[2]={n,m};
        for(ll i=1;i<=n;i++)
        {
           string a;
           cin>>a;
           for(ll j=0;j<m;j++)
           {
                if(a[j]=='#')
                {
                    mx[0]=max(mx[0],i);
                    mx[1]=max(mx[1],j+1);
                    mi[0]=min(mi[0],i);
                    mi[1]=min(mi[1],j+1);
                }
           }
        }
        cout<<(mx[0]+mi[0])/2<<" "<<(mx[1]+mi[1])/2;
        cout<<endl;
    }
    return 0;
}