力扣141A

文章目录

1. 题目链接
2. 题目代码
3. 题目总结
4. 代码分析

1. 题目链接

Amusing Joke

2. 题目代码

#include<iostream>
#include<string>
using namespace std;

int letterOfInt[30];
int letterAtDoorOfInt[30];

int main(){
    string guestName;
    string hostName;
    string letterAtDoor;
    cin >> guestName >> hostName >> letterAtDoor;
    for(int subscript = 0; subscript < guestName.length(); subscript ++){
        letterOfInt[guestName[subscript] - 'A'] ++;
    }
    for(int subscript = 0; subscript < hostName.length(); subscript ++){
        letterOfInt[hostName[subscript] - 'A'] ++;
    }
    for(int subscript = 0; subscript < letterAtDoor.length(); subscript ++){
        letterAtDoorOfInt[letterAtDoor[subscript] - 'A'] ++;
    }
    bool isOutput = false;
    for(int subscript = 0; subscript < 26; subscript ++){
        if(letterOfInt[subscript] != letterAtDoorOfInt[subscript]){
            cout << "NO";
            isOutput = true;
            break;
        }
    }
    if(!isOutput){
        cout << "YES";
    }
    return 0;
}

3. 题目总结

用时：18min

4. 代码分析

参考代码来源：

#include <iostream>
#include <algorithm>
#include <string>
 
using namespace std;
int main(){
    string s,s1,s2,snew;
    cin>>s1>>s2>>s;
    int a=s1.length();
    int b=s2.length();
    int c=s.length();
 
    if ((a+b)!=c)
    cout<<"NO"<<endl;
    
    else{
    snew=s1+s2;
    
    sort(snew.begin(),snew.end());
    sort(s.begin(),s.end());
    
    if (s==snew)
    cout<<"YES"<<endl;
    
    else
    cout<<"NO"<<endl;
    
 
    
    
    }
}