搜索与图论:染色法判别二分图
- 题目描述
- 参考代码
题目描述
输入样例
4 4
1 3
1 4
2 3
2 4
输出样例
Yes
参考代码
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 100010, M = 200010;
int n, m;
int h[N], e[M], ne[M], idx;
int color[N];
void add(int a, int b)
{
e[idx] = b; ne[idx] = h[a]; h[a] = idx; idx++;
}
bool dfs(int u, int c)
{
color[u] = c;
for (int i = h[u]; i != -1; i = ne[i])
{
int j = e[i];
if (!color[j])
{
if (!dfs(j, 3 - c)) return false;
}
else if (color[j] == c) return false;
}
return true;
}
int main()
{
scanf("%d%d", &n, &m);
memset(h, -1, sizeof h);
while (m -- )
{
int a, b;
scanf("%d%d", &a, &b);
add(a, b); add(b, a);
}
bool flag = true;
for (int i = 1; i <= n; i++)
if (!color[i])
{
if (!dfs(i, 1))
{
flag = false;
break;
}
}
if (flag) puts("Yes");
else puts("No");
return 0;
}