#include <iostream>
using namespace std;
int main(){
	const int N = 21;
	//几行几列 
	int g[N][N] = {};
	
	int n = 0;
	cin >> n;
	for (int i = 1; i <= n; i++){
		for (int j = 1; j <= n; j++){
			// 输入到几行几列 
			cin >> g[i][j];
			
			
			if (i == j || i + j == n + 1){
				//如果是这种情况就+10 
				g[i][j] += 10;
			}
		}
	}
	// 最后将他遍历出来 
	for (int i = 1; i <= n; i++){
		for (int j = 1; j <= n; j++){
			cout << g[i][j]<<' ';
		}
		cout << endl;
	}
	return 0;
}