目录

 

给定日期，输出对应是星期几

测试结果

如1900年 5月6日是星期三，计算给的日期是星期几

---

给定日期，输出对应是星期几

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
        char input[100];
        int date[3];
        int num[12] = {31,28,31,30,31,30,31,31,30,31,30,31};

        int temp;

        printf("input data:");
        while(scanf("%s", input) != EOF)
        {
                temp = 0;
                char *p;
                int num4;
                int num100;
                int num400;
                int sumDay;
                int isRun;
                num[1] = 28;

                p = strtok(input, ",");

                while(p != NULL && temp < 3)
                {
                        date[temp] =  atoi(p);
                        temp++;
                        p = strtok(NULL, ",");
                }

                num4 = date[0]/4;
                num100 = date[0]/100;
                num400 = date[0]/400;

                sumDay = (date[0] - 1)*365 + date[2] + num4 - num100 + num400;

                if((date[0]%4 == 0 && date[0] % 100 != 0)  || date[0]%400 == 0)
                        num[1] = 29;

                for(int i = 0; i < date[1] - 1; i++)
                        sumDay += num[i];

                switch(sumDay % 7)
                {
                        case 0: printf("星期日\n"); break;
                        case 1: printf("星期一\n"); break;
                        case 2: printf("星期二\n"); break;
                        case 3: printf("星期三\n"); break;
                        case 4: printf("星期四\n"); break;
                        case 5: printf("星期五\n"); break;
                        case 6: printf("星期六\n"); break;
                }

        }

        return 0;
}

测试结果

如1900年 5月6日是星期三，计算给的日期是星期几

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include<math.h>

int main()
{
        int num1900[3];
        int inputY,inputM,inputD;
        int sumDay1900;
        int sumDayInput = 0;
        int num[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
        int inputDate[3];
        int gap;

        scanf("%d,%d,%d", &inputY, &inputM, &inputD);

        num1900[0] = (1900 - 1) / 4;
        num1900[1] = (1900 - 1) / 100;
        num1900[2] = (1900 - 1) / 400;

        if((1900/4 == 0 && 1900/100 != 0) || 1900 / 400 == 0)
                num[1] = 29;

        //1900年5月6号是星期三
        sumDay1900 = (1900 - 1) * 365 + num1900[0] - num1900[1] + num1900[2] + 6; //几日在这里直接加上了，下面只加月份
        for (int i = 0; i < 5; i++)
                sumDay1900 += num[i];

        num[1] = 28;

        if((inputY/4 == 0 && inputY/100 != 0)|| inputY/400 == 0)
                num[1] = 29;

        inputDate[0] = (inputY - 1) / 4;
        inputDate[1] = (inputY - 1) / 100;
        inputDate[2] = (inputY - 1) / 400;
        sumDayInput = (inputY - 1)* 365 + inputDate[0] - inputDate[1] + inputDate[2] + inputD;
        for(int i = 0; i < inputM; i++)
                sumDayInput += num[i];

        printf("sumDayInput: %d, sumDay1900: %d inputY: %d inputM: %d inputD: %d\n",
                        sumDayInput, sumDay1900, inputY, inputM, inputD);
        if(sumDayInput > sumDay1900)
        {
                gap = sumDayInput - sumDay1900;
                switch(gap % 7)
                {
                        case 0: printf("星期三\n"); break;
                        case 1: printf("星期四\n"); break;
                        case 2: printf("星期五\n"); break;
                        case 3: printf("星期六\n"); break;
                        case 4: printf("星期日\n"); break;
                        case 5: printf("星期一\n"); break;
                        case 6: printf("星期二\n"); break;
                }

        }else {
                gap = sumDay1900 - sumDayInput;
                switch(gap % 7)
                {
                        case 0:printf("星期三\n"); break;
                        case 1:printf("星期二\n"); break;
                        case 2:printf("星期一\n"); break;
                        case 3:printf("星期日\n"); break;
                        case 4:printf("星期六\n"); break;
                        case 5:printf("星期五\n"); break;
                        case 6:printf("星期四\n"); break;
                }
        }

        return 0;
}