⭐️ 题目描述

🌟 leetcode链接：二进制链表转整数

ps：

 1 0 1
(0 << 1) + 1 = 0 + 1 = 1
(1 << 1) + 0 = 2 + 0 = 2
(2 << 1) + 1 = 4 + 1 = 5

代码：

int getDecimalValue(struct ListNode* head)
{
    int ans = 0;
    while(head != NULL)
    {
        ans = (ans << 1) + head->val; //左移1位，相当于乘以2

        printf("%d " , ans);
        head = head->next;
    }
    return ans;
}