题目链接

https://leetcode.cn/problems/grumpy-bookstore-owner/description/?envType=daily-question&envId=2024-04-23

先把最初的满意人数累加算出来，然后使用滑动窗口来模拟连续 minutes分钟不生气，计算不生气minutes分钟最大的满意数

class Solution {
    public int maxSatisfied(int[] customers, int[] grumpy, int minutes) {
        int n = customers.length;
        int res = 0;
        for (int i = 0; i < n; i++) {
            if (grumpy[i] == 0) {
                res += customers[i];
            }
        }
        int cur = 0, max = 0;
        for (int i = 0; i < n-minutes+1; i++) {
            for(int j = 0;j<minutes;j++){
                if(grumpy[i+j]==1){
                    cur += customers[i+j];
                }
            }
            max = Math.max(max, cur);
            cur = 0;
        }
        return res + max;
    }
}