一共10个电门，穷举3¹⁰次

#include<stdio.h>
#include<math.h>
int main(){
	int a[5][5], max = (int)pow(3, 10), t, op, count = 0;
	a[0][0] = a[0][2] = a[0][4] = 1;
	a[0][1] = a[0][3] = 0;
	for(int k = 0; k < max; k++){
		t = k;
		for(int i = 1; i < 5; i++){
			for(int j = 0; j < 5 - i; j++){
				op = t % 3;
				t /= 3;
				switch(op){
					case 0 : a[i][j] = a[i-1][j] & a[i-1][j+1]; break;
					case 1 : a[i][j] = a[i-1][j] | a[i-1][j+1]; break;
					case 2 : a[i][j] = a[i-1][j] ^ a[i-1][j+1];
				}
			}
		}
		if(a[4][0] == 1) count++;
	}
	printf("%d", count);//30528
	return 0;
}