我把出现的问题从项目中剥离了出来，然后再看，发现自己有点傻。

但因为项目中代码有点多，也是debug了一会儿才发现问题。

参考：

vs引发了异常: 读取访问权限冲突_qt vs 引发了异常: 读取访问权限冲突。 **other** 是 0x10。-CSDN博客

#pragma once

#include <QObject>

class QtClass  : public QObject
{
	Q_OBJECT

public:
	QtClass(QObject *parent=nullptr);
	void xxx();
	~QtClass();
private:
	int* x;
};

 

#include "QtClass.h"

QtClass::QtClass(QObject *parent)
	: QObject(parent)
{
	x = new int;
}

QtClass::~QtClass()
{}
void QtClass::xxx()
{
	*x = 3;
}

#pragma once

#include <QtWidgets/QMainWindow>
#include "ui_QtWidgetsApplication1.h"
#include "QtClass.h"
class QtWidgetsApplication1 : public QMainWindow
{
    Q_OBJECT

public:
    QtWidgetsApplication1(QtClass *m,QWidget *parent = nullptr);
    ~QtWidgetsApplication1();

private:
    Ui::QtWidgetsApplication1Class ui;
    QtClass* c;
};

#include "QtWidgetsApplication1.h"

QtWidgetsApplication1::QtWidgetsApplication1(QtClass* m, QWidget *parent)
    : QMainWindow(parent)
{
    ui.setupUi(this);
    c = m;
    c->xxx();
}

QtWidgetsApplication1::~QtWidgetsApplication1()
{}

错误写法： 

#include "QtWidgetsApplication1.h"
#include <QtWidgets/QApplication>
#include "QtClass.h"
int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    QtClass* c;
    QtWidgetsApplication1 w(c);
    w.show();
    c = new QtClass;
    return a.exec();
}

因为x没有被new，因为c没有被new。 

正确写法：

#include "QtWidgetsApplication1.h"
#include <QtWidgets/QApplication>
#include "QtClass.h"
int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    QtClass* c;
    c = new QtClass;
    QtWidgetsApplication1 w(c);
    w.show();
    return a.exec();
}