一.函数题

6-1 删除字符串中数字字符

void delnum(char* s)
{
	int i = 0;
	int j = 0;
	while (s[i] != '\0')
	{
		if (!(s[i] <= '9' && s[i] >= '0'))
		{
			s[j] = s[i];
			j++;
		}
		i++;
		
	}
	s[j] = '\0';
}

6-2 找最大值及其下标

int fun(int* a, int* b, int n)
{
	int max = a[0];
	for (int i = 1; i < n; i++)
	{
		if (max < a[i])
		{
			max = a[i];
			*b = i;
		}
	}
	return max;
}

6-3 求两数平方根之和

double fun(double* a, double* b)
{
	double sum = sqrt(*a) + sqrt(*b);
	return sum;
}

6-4 求一组数中的最大值、最小值和平均值

float fun(int a[], int n, int* max, int* min)
{
	float p = (float)a[0];
	*max = a[0];
	*min = a[0];
	for (int i = 1; i < n; i++)
	{
		p += (float)a[i];
		if (a[i] < *min)
			*min = a[i];
		if (a[i] > *max)
			*max = a[i];
	}
	return p / n;
}

6-5 两个4位正整数的后两位互换

void fun(int* p, int* q)
{
	int a1 = 0, a2 = 0;
	int b1 = 0, b2 = 0;

	
	
	while (*p > 100)
	{
		a1 = *p % 10;
		*p /= 10;
		a2 = *p % 10;
		*p /= 10;
	}
	
	while (*q > 100)
	{
		b1 = *q % 10;
		*q /= 10;
		b2 = *q % 10;
		*q /= 10;
	}
	*p = *p * 100 + b2 * 10 + b1;
	*q = *q*100 + a2 * 10 + a1;

}

6-6 判断回文字符串

bool palindrome(char* s)
{
    int left = 0;
    int right = strlen(s) - 1;
    while (left < right)
    {
        if (s[left] != s[right])
            return false;
        left++;
        right--;
    }
    return true;
}

二.程序题

7-1 求矩阵每行元素的和

#define N 6
int main()
{
	int m, n, sum = 0;
	int a[N][N];
	int(*p)[N];
	int i, j;
	p = a;
	scanf("%d%d", &m, &n);
	for (i = 0; i < m; i++)
	{
		for (j = 0; j < n; j++)
		{
			scanf("%d", &*(*(p + i) + j));
		}
	}
	for (i = 0; i < m; i++)
	{
		sum = 0;
		for (j = 0; j < n; j++)
		{
			sum = sum + *(*(p + i) + j);
		}
		printf("%d\n", sum);
	}
	return 0;
}